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14x^2+27x-17=0
a = 14; b = 27; c = -17;
Δ = b2-4ac
Δ = 272-4·14·(-17)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-41}{2*14}=\frac{-68}{28} =-2+3/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+41}{2*14}=\frac{14}{28} =1/2 $
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